Estimate how many Assembly Language commands are in a 32K executable. The Linux kernel is about 5.1MB in size. If the Linux kernel was written in Assembly Language, how many instructions would that be? Estimating the Number of Assembly Language Instructions in a 32K

How many Assembly Language Instructions are in 32k?

The assembly language instructions can be described as instructions specific to a particular processor that are required for executing a function. Patil and Rathee (2018) state that even though Assembly language instructions are processor-specific it can still be used to perform a function. The size of an executable 32K and its instruction set are important factors in computing the Assembly language instructions. The processor can store more instructions in 32K if it has a wider set of instructions.   An assembly language instruction may have eight bytes on average. A 32k executable could contain up to 496 instructions if it has been written using assembly language. This number can be reduced depending on context, such as whether the code is optimized or contains unused data.   The total size of an Assembly Language program, such as the Linux kernel’s Linux kernel, must be considered when calculating how many instructions are in it. Andrade (2018) estimates that the Linux kernel measures approximately 5.1MB. It would have around 414,000 instructions if the kernel were written in assembly languages, several orders of magnitude greater than 32K executables.  Cont…

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