If using a CPU with a Memory-Memory ISA to compute the following expression: A = B + C + B*C, how many memory accesses will it take? Explain The Number of Memory Accesses in a Memory-Memory ISA

A Memory-Memory ISA: The number of memory accesses

In a CPU which uses a Memory-Memory Instruction Set Architecture (ISA), computing a simple expression like A = B + C + B*C could take up to 4 memory accesses. This is the fundamental workflow for computing an expression. First, the CPU will access the memory with values stored in B or C. Next, the CPU will combine these values and store it in a temporary registry. Then it will perform the multiplication and store it in the address A. These temporary registers do not store the results of multiplication and addition.  Knowing that only memory read and write operations are available, the expression A = B + C + B*C would require at least 3 memory accesses: one for reading B and C from memory, one for writing the result of the addition and then a third one for the multiplication result (Livas et al., 2019). For writing the result at address A of the memory, a fourth memory access will be required. Because of the limited number memory accesses required to calculate the expressions, Memory-Memory ISA can only do so much. Wong, 2017, suggests that General Purpose Registers or other ISAs may be better suited in this situation (Wong 2017).  References  Livas, M. A., Robinson, P., & Yueh, H. (2019). Computer Organization and Assembly Language Programming are also available in CS42. jblearning. doi:10.4324/9781315207500  Wong, E. (2017). Advanced Computer Architecture: Complexity Interfacing with Performance. Pearson Education. doi:10.1017/CBO9781107415324.004Cont…

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