# Lets consider the instruction lw \$4, X(\$5). Now if you have an array A[5] and the base address of that array is 256 in decimal then find the value of X in the lw instruction in case of 128-bit architecture. Operand Format of Load Word Instruction in a 128-Bit Architecture

Operating Format of Load word Instructions in 128-Bit Architecture

A load word instruction (lw 4), X(\$5) is a type of RISC-style assembly-language instruction that’s used with a 128 bit architecture. This instruction is used to retrieve a word from the memory, and then store it in a register. This instruction stores \$5 in the source register and 4 in the target register. Here, X denotes an offset value, which will determine the address to which the data is to be downloaded (Aditya 2015).  We need to subtract A from an array’s base address in order to convert the memory address (X) into an offset value.[5] Which is 256 in decimal, from A[0] (Say A)[0] = 0x256). Hence, X= 0x256- 256 = 0x0 (Dec). With other words, X equals 0. In other words, X = 0, i.e. the data is obtained from A’s base address[5] (Deb et al., 2021).  The value of X within the lw instruction therefore is 0.   References  Aditya, R. (2015). Computer Network. Delhi: S. Chand.  Deb, C., Lewis, D., Muthuswamy, P., & Kharbanda, K. (2021). Computer Architecture: Design & Performance. Harlow, England: Pearson.Cont…

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