Show the balanced equation and the calculation of the number of moles and grams of CO2 formed from 25.4 grams of C8H18, show answers to 3 significant figures. Balanced Equation for the Complete Combustion of Octane

For the complete combustion of Octane, a balanced equation is required
You can represent the complete combustion of Octane in O2 to make carbon dioxide (CO2) or water (H2O), using this balanced equation 2C8H18+25O2. 16 CO2+18 H2O Calculation for Moles or Grams of Co2 We can calculate the number and moles of carbon dioxide from the 25.4g of C8H18. This is done using the mole to mole ratio in the balanced equation as well as the molal mass of CO2 (Kumar, 2020; Singh 2020). You can calculate the moles of C8H18’s 25.4 grams by using the molar weight of CO2 (44.1 g/mol). There are 16 moles produced from C8H18 because the C8H18-CO2 molar relationship is 2:16. For every 2 moles C8H18 there will be CO2. We would get 12.7 moles from 25.4 grams C8H18. (25.4g C8H18 / (2) mol C8H18 (16 molCO2) = 12.7mol CO2). To calculate the total mass of the CO2, we multiply the moles produced by the molar CO2 mass (12.7 molCO2 x 44.01g/mol = 562 g CO2). C8H18 is 25.4g and produces 562 grams CO2. Cont…
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