Thymol has the formula C10H14O and its
combustion can be written as:
C10H14O(l) + 13 O2(g) _ 10
CO2(g) + 7 H2O(l)
The change in enthalpy of combustion of 1 mole of thymol at
298.15 K is determined to be -5660 kJ at constant pressure.
What is _E for this reaction at 298K?
Enter your answer to 4 significant figures in units of kJ. Be
sure to include the sign.
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